X^2+11x-146=0

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Solution for X^2+11x-146=0 equation: 



X^2+11X-146=0

a = 1; b = 11; c = -146;
Δ = b2-4ac
Δ = 112-4·1·(-146)
Δ = 705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{705}}{2*1}=\frac{-11-\sqrt{705}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{705}}{2*1}=\frac{-11+\sqrt{705}}{2}
$

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